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Inis2005
a fost răspuns

1. Calculati: (3·5¹²+2·5¹²)÷5¹¹; 8¹⁶÷(2·2²·4¹⁰)²-2¹-2⁰; (10¹⁰-10⁹)÷(10⁹-10⁸); (2²·2⁴)²÷4⁶-16⁴÷8⁵÷2¹ ÷2⁰. ajutor dau coroana

Răspuns :

(3•5¹²+2•5¹²):5¹¹=[5¹²•(2+3)] :5¹¹
=(5¹²•5¹):5¹¹
=5¹³:5¹¹
=5 la puterea13-11
=5²
Icecon2005
(3·5¹²+2·5¹²):5¹¹=5¹²(3+2):5¹¹=5×5=25

[tex]2^{16*3}:( 2^{3} *2^{20})^{2} -2-1= \\\\ 2^{48} :2^{120} -3= [/tex]


[tex] ( 10^{10}- 10^{9}):(10^{9}-10^{8})=10^{9}(10-1):10^{8}(10-1)= \frac{9*10^{9}}{ 10^{8}*9 } =10[/tex]

[tex](2^{2}*2^{4} ):4^{6}- 16^{4}: 8^{5} : 2^{1}: 2^{0} = \\ \\ (2^{6}:2^{12})-(2^{4} )^{4} :2 ^{3*5}:2:1= \\ \\ \frac{1}{ 2^{2}} - 2^{16}: 2^{15}:2:1 \\ \\ \frac{1}{ 2^{2}}-1= \\ \\ \frac{1}{4}-1= \\ \\= - \frac{3}{4} [/tex]

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