M(miu)=(1gH+35,5gCl)/mol= 36,5g/molHCl
M= (27gAl+3x35,5gCl)/mol=133,5 g/mol AlCl3
Calculez masa de acid din solutie
c/100=md/ms
36,5/100= md/600----->md= 219gHCL
din ecuatie calculez masa de AlCl3 care se formeaza din masa obtinuta de acid
6mol........2mol
2Al +6HCl---> 2AlCl3 +3H2
6x36,5........2x133,5g
219g.............x=.................calculeaza x !!!!