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a fost răspuns

se supun clorurarii fotochimice 192g metan, amestecul de reactie contine CH3, Cl,CH2Cl2,
CHCl3 si metan nereactionat in raport molar de 2:2:1:1
a)ecuatiile react. chimice
b)masa de cloroform
c)Vsolutiei 0,2 molare de HCl daca intreaga cantitate de acid se dizolva in apa

Răspuns :

Moonlight01
MCH4=16g/mol

n=m/M=192/16=12 moli CH4

      x..........x...............x...........x
a) CH4 + Cl2 => CH3Cl + HCl
y.............2y...............y.............2y
CH4 + 2Cl2 => CH2Cl2 + 2HCl
z..............3z............z.............3z
CH4 + 3Cl2 => CHCl3 + 3HCl
w...............w
CH4 => CH4

b) x/y=2/2 => y=2x/2

x/z=2/1 => z=x/2

x/w=2/1 => w=x/2

x+y+z+w=12 => x+2x/2+x/2+x/2=12 => 6x/2=12 => x=4 moli 

y=4 moli

z=2 moli

w=2 moli

m CHCl3= 2*119,5=239g

b) x+2y+3z=4+2*4+3*2=18 moli HCl

Cm=n/Vs=>Vs=n/Cm=18/0,2=90L HCl

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