RÄspuns :
a=233.493; b=233.493-11.278= 222.215=> 233.493+222.215+c=659.475;c= 659.475 -222.215= 437.260-233.493=203.967
Notam cu a, b, c - cantitatea de cereale din cele trei depozite.
a + b + c = 659.475 kg
a = 233.493 kg
b = a - 11.278
b = 233.493 - 11.278 = 222.215 kg
c = 659.475 - a - b
c= 659475 -233.493 - 222.215
c= 203.767 kg
a + b + c = 659.475 kg
a = 233.493 kg
b = a - 11.278
b = 233.493 - 11.278 = 222.215 kg
c = 659.475 - a - b
c= 659475 -233.493 - 222.215
c= 203.767 kg