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Fie numerele a si b. Calculati 2a-2^3*5^3*8b.

a+(1+2+3+...+2000):2000*4 si b=(3^17:9^8)^2000:3^2000

Răspuns :

Renatemambouko
a=(1+2+3+...+2000):2000*4 =2000*2001:2 :2000*4=2001*2=4002

b=(3^17:9^8)^2000:3^2000=(3^17:3^16)^2000:3^2000=(3^1)^2000:3^2000=1

2a-2^3*5^3*8b=2*4002-8*125*8=8004-8000=4

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