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Calculati:(4^4: 2^6 + 3^121 : 9^60 + 25^3: 5^4) :4
merci.

Răspuns :

Mihaelarosca73
((2'2)'4:2'6+3'12:(3'2)'60+(5'2)'3:5'4):4= (2'8:2'6+3'121:3'120+5'6:5'4):4= 2'2+3'1+5'2):4= (4+3+25):4= 32:4=8
[tex](4^4:2^6+3^{121}:9^{60}+25^3:5^4):4= \\ \\ (2^2)^4:2^6+3^{121}:(3^2)^{60}+(5^2)^3:5^4):4= \\ \\ (2^8:2^6+3^{121}:3^{120}+5^6:5^4):4= \\ \\ (2^{8-6}+3^{121-120}+5^{6-4}):4= \\ \\ (2^2+3^1+5^2):4= \\ \\ (4+3+25):4= \\ \\ 32:4=\boxed{8}[/tex]

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