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Stiind ca: -3a+5y=7, calculati:
(6-5y+3x)+(8-5y+3x)^2+.....+(6-5y+3x)^99+(8-5y+3x)^100
P.S.Dati mi direct rezolvarea

Răspuns :

Christian02
(6-(-3x+5y))+(8-(-3x+5y))^2+...+ (6-(-3x+5y))^99 + (8-(-3x+5y))^100=
= 6-7 +(8-7)^2+(6-7)^3 +...+(6-7)^99 +(8-7)^100 = -1+1-1+1...-1+1(cifra 1 apare de 100 de ori, 50 cu - si 50 cu +, deci toti se reduc) = 0

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