Răspuns :
a+3b=7,3b+2c=9,c+d=1
2a+15b+10c+4d = (2a+6b) +( 9b+6c)+ (4c+4d)=2*(a+3b)+3*(3b+2c)+(c+d)=
=2*7+3*9+1=14+27+1=42
a+3b=7
3b+2c=9
c+d=1
2a+15b+10c+4d=2(a+3b)+3(3b+2c)+4(c+d)=2x7+3x9+4x1=14+27+4=55
3b+2c=9
c+d=1
2a+15b+10c+4d=2(a+3b)+3(3b+2c)+4(c+d)=2x7+3x9+4x1=14+27+4=55