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Cristi4cata
a fost răspuns

a+b+c=121
a÷b=10 r 5
b÷c=5 r 4
aflati numerele a,b,c

Răspuns :

Alitta

daca : a:b=10 (r. 5)  => a=10b+5

    si    b : c = 5  (r. 4)    => b=5c+4

                 =>   a+b+c = 121

          adica: 10b+5 + b + c = 121

                    10(5c+4)+5c+4)+c = 121

                    50c+5c+c = 121 - 40 - 4

                                  56 c = 77  |:7

                                   c = 11/8

                                   b = 5*11/8+4=(55+32)/8 = 87/8

                                   a = 10*87/8+5=(870+40)/8 = 910/8

=> 

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