-prin clorurarea propenei la 500C, are loc o substitutie alilica(ramane dubla legatura)
CH2=CH-CH3+ CL2---> CH2=CH-CH2Cl +HCl
SAU C3H6 +Cl2---> C3H5Cl+HCl-----. > din masa propenei,42g. dispare 1H(1g) si apare 1 Cl(35,5g), deci la 42g......este o crestere de 34,5g
100g................................c%=82,14%
prin hidroliza clorurii de alil, rezulta alcoolul alilic:
CH2=CH-CH2Cl+HOH--->CH2=CH-CH2OH +H2O