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a fost răspuns

Calculați:
3*(2^5+2^4-2^3)+[25^10-(5^5)^4]:(3^100-2^100)=
2*3^2-81^10:27^5:[5^3-5*(4^2-11)^2+3^5]^5=
125^5:25^7+3*[16^3*4^2:8^5+(7^5*3^4)^10:(7^2)^25:9^20]=

Răspuns :

Spidie
1.
3*(2⁵+2⁴-2³)+[25¹⁰-(5⁵)⁴ ]:(3¹⁰⁰-2¹⁰⁰)=3*2³*(2²+2- 1)+(5²⁰-5²⁰ ):(3¹⁰⁰-2¹⁰⁰)=
=3*2³*5+5²⁰*(1-1):(3¹⁰⁰-2¹⁰⁰)=3*2³*5+5²⁰*0:(3¹⁰⁰-2¹⁰⁰)=3*8*5+0=120
2.
2*3²-81¹⁰:27⁵:[5³-5*(4²-11)²+3⁵]⁵=2*3²-3⁴⁰: 3¹⁵:[5³-5*5²+3⁵]⁵=
=2*3²-3²⁵: (3⁵)⁵=2*3² -1=2*9-1=17
3.
125⁵: 25⁷+3*[16³*4²: 8⁵+(7⁵*3⁴)¹⁰:(7²)²⁵: 9²⁰]=
= (5³)⁵: (5²)⁷+3*[(2⁴)³*(2²)²:(2³)⁵+ 7⁵⁰*3⁴⁰: 7⁵⁰: (3²)²⁰] =
=5¹⁵:5¹⁴ +3*(2¹²*2⁴: 2¹⁵+1)=5+3*(2+1)=5+9=14





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