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3/2-(-5/4)+(-7/5)-(-41/40)=
(-2/3+4/5+1)-(-4/3+2/5-2)+(-2+3/5)=
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Răspuns :

Iakabcristina2
3/2-(-5/4)+(-7/5)-(-41/40)=3/2 + 5/4 - 7/5 + 41/40
Se aduce la numitor comun, 40
(3x20+5x10-7x8+41)/40=(60+50-56+41)/40=95/40=19/8=2 intregi 3/8

(-2/3+4/5+1)-(-4/3+2/5-2)+(-2+3/5)=-2/3+4/5+1+4/3-2/5+2-2+3/5=
-2/3+4/5+1+4/3-2/5+3/5
Se aduce la numitor comun, 15
(-2x5+4x3+1x15+4x5-2x3+3x3)/15=(-10+12+15+20-6+9)/15=40/15=8/3=2 intregi 2/3

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