Rezolvati in N³ ecuatia
(x+1)^2+(y-2)^2+(z-3)^2=25
avem urmatoarele variante
x+1=5, y-2=0, z-3=0 care ma duce la x=4; y=2; z=3
x+1=0, y-2=5 z-3=0 ⇒x=-1; y=2 z=3 nu convine
x+1=0; y-2=0 z-3=5...nu convine dincauzax=-1
x+1=3; y-2=4 z-3=0 ⇒(x,y,z) =(2;6;3...)
x+1=3 y-2=0 z-3=4 ⇒(x;y,z)=(.2;2'7..)
x+1=4; y-2=3 z-3=0 ⇒(x;y,z)=(3;5;3...)
x+1=4; y-2=0 z-3=3⇒(x;y,z) = (3.2;6)
Deci 5 solutii in N³
