Răspuns :
Notam numerele cu a si b
a+b=375
b:a/4= 6 rest 25
b=25+6*a/4
b=25+3a/2 (prin simplificare)
înlocuim in ecuatia initala: a + 3a/2+25=375
(2a+3a)/2=350
5a=700
a=140 => b=375-140 => b=235
a+b=375
b:a/4= 6 rest 25
b=25+6*a/4
b=25+3a/2 (prin simplificare)
înlocuim in ecuatia initala: a + 3a/2+25=375
(2a+3a)/2=350
5a=700
a=140 => b=375-140 => b=235
a+b=375
b:a/4=6 rest 25
b=a/4×6+25⇒b=2a/3+25
b=2a/3+25 si a+b=375
a+2a/3+25=375
3a+2a+75=375×3
5a=375×3-75
5a=1050⇒a=210
a+b=375⇒210+b=375⇒b=375-210⇒b=165
a=210 si b=165
verificare
a+b=375⇒210+165=375⇒375=375
b:a/4=6 rest 25
b=a/4×6+25⇒b=2a/3+25
b=2a/3+25 si a+b=375
a+2a/3+25=375
3a+2a+75=375×3
5a=375×3-75
5a=1050⇒a=210
a+b=375⇒210+b=375⇒b=375-210⇒b=165
a=210 si b=165
verificare
a+b=375⇒210+165=375⇒375=375