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Ioanaelena123
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calculati
2+4+6+.........+100=

Răspuns :

MariMari
2+4+6+...+100=2(1+2+...+50)=2×50×51÷2=50×51=2550
Anamariaangel
[tex]1+2+3+...+n= \frac{n(n+1)}{2} [/tex]

[tex]2+4+6+...+100=2*(1+2+3+...+50)=2* \frac{50(50+1)}{2} = 50*51[/tex]=[tex]2550[/tex]


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