1. 44g CO2...........6,023*10^23 molecule
xg CO2................150*10^23 molecule
x=44*150/6,023=
2. 22,4L CO2........6,023*10^23 molecule
x L CO2................150*10^23 molecule
sau
pV=nRT=>n=pV/RT=1*75/0,082*273=3,35 moli CO2
1mol CO2......6,023*10^23 molecule
3,35 moli CO2.......x molecule
3. n=V/Vm=75/22,4=3,348 moli NH3
1 mol NH3......6,023*10^23 molecule
3,348 moli........x= 20,166*10^23 molecule
4. MNH3=17g/mol
n=m/M=>m=17*3,348=56,919g NH3
