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Daca a+ b+ c=18 iar 2a+b+2c=25 atunci calculati (a+c) × ( 3a+2b+3c ) = ?

Răspuns :

Patrissia
2a+b+2c+a+b+c=25+18=43
2(a+c)=25-b=>a+c=(25-b)/2
a+b+c=18=>b+(25-b)/2=18=>(2b+25-b)/2=18=>b+25=36=>b=11
a+c=(25-b)/2=>a+c=(25-11)/2=>a+c=14/2=>a+c=7
(a+c) × (3a+2b+3c)=7 × 43=301

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