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Masatrst1
a fost răspuns

3a+3b+3c=
2x+2y+2z=
8+4a+16b=
5x-5y+5z=
15+3a+3b=
4•7-4•2+5•2+5•7=
5•7+7•3-(4•5+4•3)=

Răspuns :

ClauDiiaaa
3a+3b+3c=3 (a+b+c)
2x+2y+2z=2 (x+y+z)
8+4a+16b=4 (2+a+4)
5x-5y+5z=5 (x-y+z)
15+3a+3b=3 (5+a+b)
4×7-4×2+5×2+5×7=4 (7-2)+5 (2+7)
5×7+7×3-(4×5+4×3)=7 (5+3)-4 (5+3)=(7-4)(5+3)

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