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descompuneti in factori
a} x ²-4x plus 3
b}x² plus 10x plus 24
c}a² b- 5a² b plus 6a²
d}a² -14x plus 48
f}tz²-6tz plus 16z

URGENT VA ROGGGGGGGGGGGGGGGGG DAU 30 DE puncte

Răspuns :

Emanuelgreavu1
a)x²-4x+3=x²-3x-x+3=x(x-3)-(x-3)=(x-3)(x-1)
b)x²+10x+24=x²+6x+4x+24=x(x+6)+4(x+6)=(x+6)(x+4)
c)a²b-5a²b+6a²=a²(b-5b+6)=a²(-4b+6)
d)x²-14x+48=x²-6x-8x+48=x(x-6)-8(x-6)=(x-6)(x-8)
e)tz²-6tz-16t=tz²-2tz+8tz-16t=tz(z-2)+8t(z-2)=(z-2)t(z+8)

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