A,Na= 23g/mol
miu(M) H2O= 18g/mol
miu(M),NaOH= (23gNa+16gO+1gH)/mol=40g/mol
ecuatia reactiei:
2x23g.......2x18g.........2x4og.........2g
2Na + 2H2O---------> 2NaOH+ H2
2,3g......m= ...................m1=.......m2=
m= 2,3x18/23
m1= 2,3x40/23
m3=2,3x2/23 calculeaza masele !!!!