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Mili772005
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aratati ca nr A=(5+10+15+..........+200)/41   este patrat perfect

Răspuns :

Bunicaluiandrei
5( 1+2+3+........+40) /41 =( 5·40·41/2)÷41 = 100 = 10² =p.p.
0000000
[tex]A= \frac{5+10+15+..........+200}{41} \\ \\ A= \frac{5(1+2+3+...+40)}{41} \\ \\ A= \frac{5 \frac{40(40+1)}{2} }{41} \\ \\ A= \frac{5*20*41}{41} \\ \\ A=5*20 \\ \\ A=100=10^2~deci~A=p.p[/tex]

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