Răspuns :
a)ΔMNK- dreptunghic
⇒ TP⇒ MK² = MN² +NK²⇒ MK² = 600² +450² =360000 + 202500
MK² = 562500⇒ MK = 750 m
b) A ΔMNK= MN*NK :2= 600 *450 :2=300*450=135000m²
c) d(N, MK) = h in Δ dreptunghic
h= MN*NK : MK= 600*450 : 750=360m
d) KM = 750m
5400 m ....60 min
750 m ....x min
x=750*60:5400 =8 minute si 20 secunde
⇒ TP⇒ MK² = MN² +NK²⇒ MK² = 600² +450² =360000 + 202500
MK² = 562500⇒ MK = 750 m
b) A ΔMNK= MN*NK :2= 600 *450 :2=300*450=135000m²
c) d(N, MK) = h in Δ dreptunghic
h= MN*NK : MK= 600*450 : 750=360m
d) KM = 750m
5400 m ....60 min
750 m ....x min
x=750*60:5400 =8 minute si 20 secunde