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Forearazvan98
a fost răspuns

cum se face inecuatia 7xX-3<5xX+13 si 2xX+4<X+16

Răspuns :

Deva
7xX-3<5xX+13
7x-5x<3+13
2x<16
x<8
x apartine{o,1,2,3,4,5,6,7}
2xX+4<x+16
2x-x<16-4
x<12
xa partine{0,1,2,3,4,5,6,7,8,9,10,11}
1.
7x-3-5x<13
2x-3<13
2x<13+3
2x<16
x<16:2
x<8
2.
2x+4-x<16
x+4<16
x<16-4
x<12

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