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Busteneastefan
a fost răspuns

cat face inecuatia 18x-14 mai mare sau egal decat 2 ori(3x+5)

Răspuns :

Deva
18x-14>sau=2x(3x+5)
18x-14>sau=6x+10
12x>sau=24
x>sau =24/12=2
xapartie {2,3,...}
18x-14≥2(3x+5)
18x-14≥2*3x+2*5
18x-14≥6x+2*5
18x-14≥6x+10
18x-14-6x≥10
12x-14≥10
12x≥10+14
12x≥24
x≥24:2
x≥2

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