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Reactioneaza aluminiu cu aici clorhidric si se formeaza 8,96 l gaz.Calculati masa de aluminiu folosita si masa solutiei de acid clorhidric de concentratie 35,5% necesara in reactie.Dau coroana 50pts va rog

Răspuns :

Moonlight01
n=V/Vm=8,96/22,4=0,4 moli gaz (H2)

2Al + 6HCl -> 2AlCl3 + 3H2

2*27g Al.......................3 moli H2
xg Al.............................0,4 moli H2

x=54*0,4/3= Calculeaza!!

6*36,5g HCl.......................3 moli H2
xg HCl................................0,4 moli H2

x=6*36,5*0,5/3=36,5g HCl (md)

C=md/ms*100 => ms=md*100/C=36,5*100/35,5= Calculeaza !!

MHCl = AH+ACl=1+35,5=36,5g/mol

MAl=27g/mol

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