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643-[(X-162)/5+159]=454

Răspuns :

Andrew55

643-[(X-162)/5+159]=454

643-(X-162)/5-159=454

643-(X-162)/5-159-454=0

30-(X-162)/5=0 /x5 (inmultim relatia cu 5)

150-x+162=0

312-x=0⇒x=312

V:643-[(312-162)/5+159]=

643-150/5-159=

643-30-159=454
643-{(x-162):5+159]=454
[(x-162):5+159]=643-454=189
(x-162):5=189-159=30
x-162=30x5=150
x=150+162
x=312

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