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a fost răspuns

calculati masa de hidroxid de sodiu de concentratie 30% necesara in reactia cu 182g de fenol

Răspuns :

Moonlight01
Mfenol=94g/mol
MNaOH=40g/mol

C6H5-OH + NaOH -> C6H5-ONa + H2O

94g C6H6O.......................40g NaOH
182g C6H6O.......................xg NaOH

x=40*182/94=77,4468g NaOH

C=md/ms*100 => ms=md*100/C=7744,68/30=

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