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Determina formula moleculara a unei hidrocarburi ce contine 17,25 % H si are masa moleculara 58.

Răspuns :

Moonlight01
%C=100-%H=100-17.25=82.75

C=82.75/12=6.895 ||=> 1 atom C

H=17.25/1=17.25 ||=> 2.5 atomi H

F.B => (CH2,5)n=58 => 14.4n=58=>n=4

C4H10

sau

nC=%C*M/AC*100=82.75*58/1200=4 atomi C

nH=%H*M/AH*100=17.25*58/100=10 atomi H

C4H10

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