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DeeaD16
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Peste 20g de CaCo3 se adauga solutie de acid acetic in exces. In urma reactiei care are loc se degaja 3.584 dm^3 CO2 (c.n.).
a) calculeaza puritatea carbonatului de calciu
b) calculeaza masa de acetat de calciu obtinuta.

Răspuns :

Moonlight01
m/M=V/Vm=>m=M*V/Vm=44*3,584/22,4=7,04g CO2

CaCO3 + 2CH3-COOH -> (CH3-COO)2Ca + CO2 + H2O

100g CaCO3.........................44g CO2
xg..........................................7,04g CO2

x=704/44=16g

a) p=mpur/m impur*100 = 16/20*100= Calculeaza !!

b) M acetat = 158g/mol

158g acetat,,,,,,,,,,,,,,,,,,,,,,,44g CO2
xg......................................7,04g CO2

x=158*7,04/44=25,28g acetat

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