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Costachelarisa4
a fost răspuns

Determinati numerele naturale de forma ab stiind ca :
ab1+2ab+ab0=6844
DAU CORONITA PLS AJUTATI-MA REPEDE

Răspuns :

Capsunica35
100a+10b+1+200+10a+b+100a+10b=684
210a+21b+201=684
210a+21b=684-201
21(10a+b)=483
10a+b=483:21
10a+b=23
ab=23 cu bara sus
Ttttttt1bgdfv
ab1+2ab+ab0=684

Daca a=2, b=1
=> 211+221+210= 432+210 =642 => F
Daca a=2, b= 3
231+223+230= 454+230= 684

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