Răspuns :
S=nx(n+1):2
2+4+6+.................+20 ( avem factor comun 2)
2x(1+2+3+.............+10)= ( aplicam formula pentru suma Gauss)
2x[10x(10+1):2]=
2x[10x11:2]=
2x(110:2)=
2x55=110
2+4+6+.................+20 ( avem factor comun 2)
2x(1+2+3+.............+10)= ( aplicam formula pentru suma Gauss)
2x[10x(10+1):2]=
2x[10x11:2]=
2x(110:2)=
2x55=110
2+4+6+....20=30
2(1+2+3+....+5)=2*15
1+2+3+.....+5=[5*(5+1)]:2=5*6:2=5*3=15
2(1+2+3+....+5)=2*15
1+2+3+.....+5=[5*(5+1)]:2=5*6:2=5*3=15