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Alecuionut75
a fost răspuns

Se ard in clor 2,3 grame de sodiu metalic. Calculati in grame si moli cantitatea de produs.

Răspuns :

Mihaiimbrisca
2×23g 2×58,5g
2Na + Cl2 => 2NaCl
2,3g xg
MNa=ANa=23g
MNaCl=ANa+ACl=23+35,5=58,5g
x=2,3×2×58/2×23
x=5,8 g
2mol 2mol
2Na + Cl2c=> 2NaCl
0,1mol a
n=m/M
n=2,3/23
n=0,1mol
a=0,1×2/2
a=0,1 mol

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