n=m/M=1,27/127=0,01 moli s.o
143,5g AgCl...........................35,5g Cl
2,87g AgCl.............................x=0,71g Cl
44g CO2.....................12g C
1,76g CO2...................x=0,48g C
mH=1,27-0,71-0,48=0,08g H
n=m/M=0,48/12=0,04 moli C
n=m/M=0,08/2=0,04 moli H
n=m/M=0,71/35,5=0,02 moli Cl
0,01 moli s.o................0,04 moli C.....0,04 moli H2.....0,02 moli Cl
1 mol...........................x=4 atomi C.......y=8 atomi H.....z=2 atomi Cl
F.M => C4H8Cl2