x+y=8
y+2z=35
a)7x+1y+6z=?
b)4x(2z+1y)+3X+3Y=?
a)7x+1y+6z=?
6x+x+y+6z=6x+8+6z
7x+y+2z+4z=7x+35+4z
6x+6z+8=7x+4z+35
6x+6z=7x+4z+27
6x+2z=7x+27
2z=x+27
x+y=8 (2z-27)-y=8 2z-y=35 2z+y=35
y=0
2z=35
x+27=35
x=8
7x8+0+6x35=56+210=266
b)4x(2z+y)+3X+3y=?
4x35+24=140+24=164
