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Daca 3a+2b+2c=45 si a+2b+2c=99, aflati a+b+c.

Răspuns :

3a+2b+2c+a+2b+2c=45+99 4a+4b+4c=144 4(a+b+c)=144=>a+b+c=144:4=>a+b+c=36
Alitta
3a + 2b + 2c = 45  adunat cu 
 a  + 2b + 2c = 99
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4a + 4b + 4c = 144
4*(a+b+c) = 144
    a+b+c = 144:4 = 36

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