C1=concentratie sol. NaOH=20%
md1=masa dizolvata NaOH
ms1=masa solutie NaOH
M1=nr. moli NaOH
C2=concentratie sol. HCl=20%
md2=masa dizolvata HCl
ms2=masa solutie HCl
M2=nr. moli HCl
NaOH + HCl ---------> NaCl + H2O
x moli x moli x moli x moli
c1=(md1/ms1)*100
(Banuiesc ca este 100 g solutie de NaOH, trebuia scris ceva mai clar)
md1=(c1*ms1)/100=(20*100)/100=20 g NaOH
M1=md1/(masa molara NaOH)=20/40=0,5 moli NaOH
x=0,5 moli -----> M2=0,5 moli HCl
M3=nr. moli NaCl=0,5 moli NaCl
md2=M2*(masa molara HCl)=0,5*36,5=18,25 g HCl
masa de sare=masa de NaCl=M3*(masa molara NaCl)=0,5*58,5=29,25 g NaCl (sare)
