Inainte de a rezolva trebuie sa stii ca 1 mol de substanta este egal cu NA-nr lui Avogadro, care este egal cu 6,023*10^23 particule
a) 1 kmol = 1000 moli
0,01 kmoli = 10 moli CO
1 mol CO.....................6,023*10^23 particule
10 moli CO.................x=6,023*10^24 particule
b) 1dm3=1L
n=V/Vm=0,224/22,4=0,01 moli O2
1 mol O2.....................6,023*10^23 particule
0,01 moli O2...............x=6,023*10^21 particule
c) MC2H2=2AC+2AH=2*12+2*1=26kg/kmol
n=m/M=2/26=0,076923 kmoli C2H2 = 76,923 moli C2H2
1 mol C2H2......................6,023*10^23 particule
76,923 moli C2H2.............x=463,3*10^23 particule
