2Al + 6HCl = 2AlCl3 + 3H2
a) MAl=27g/mol
MHCl=AH+ACl=1+35.5=36.5g/mol
2*27g Al ...........6*36.5g HCl
270g Al..............x=1095g HCl (md)
C=md/ms*100=>ms=md*100/C=109500/36.5= Calculează !!
b) 2*27g Al..................3*22,4 L H2
270g Al.......................x= Calculează!!!