Răspuns :
[tex]\displaystyle (3^{201}+3^{204}):(3^{201}-3^{200}+3^{199})=\\\\ =\frac{3^{201}+3^{204}}{3^{201}-3^{200}+3^{199}}=\\\\ =\frac{3^{199+2}+3^{199 + 5}}{3^{199+2}-3^{199+1}+3^{199}}=\\\\ =\frac{3^{199}\times 3^2+3^{199}\times 3^5}{3^{199}\times 3^2-3^{199}\times 3^1+3^{199}}=\\\\ =\frac{3^{199}( 3^2+ 3^5)}{3^{199}( 3^2- 3^1+1)}=\\\\ =\frac{ 3^2+ 3^5}{ 3^2- 3^1+1}=\\\\ =\frac{9+ 243}{ 9- 3+1}=\frac{252}{ 7}=\boxed{36} [/tex]
