A,Mg= 24g/mol;A,MgSO4= (24gMg+32gS+4x16gO)/mol= 120g/mol
M,H2SO4= (2X1gH+32gS+4X16gO)/mol= 98g/mol
-ecuatia reactiei este:
1mol 1mol 1mol
Mg + H2SO4----> MgSO4+ H2
24g...........98g.......120g
240g......m=............m'=
-calculez ,din ecuatie,masa de acid si masa solutiei de acid
m=240x98/24=980g H2SO4= masa dizolvata in solutie=md
c/100= md/ms; 10/100= 980/ms-----------------------> ms= .............calculeaza !
-calculez, din ecuatie, masa de sulfat de magneziu
m'=240x120/24 g MgSO4=................................CALCULEAZA!!!
