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DieDiana
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C)determinati nr de forma abc stiind ca abc + 5abc + abc0 =7532

Răspuns :

Danait
abc + 5abc + abc0 =7532; 100a+10b+c+5000+100a+10b+c+1000a+100b+10c+0=7532; 1200a+120b+12c+5000=7532; 1200a+120b+12c=7532-5000; 1200a+120b+12c=2532/:12; 100a+10b+c=211⇒a=2;b=1;c=1.