a) [tex]8 ^{18}-7*8 ^{17} = 8 ^{17}(8-7)=8 ^{17}=(2^{3})^{17}=2^{51}\\
16^{14}-15*16^{13}=16^{13}(16-15)=16^{13}=(2^{4})^{13}=2^{52}\\ [/tex]
Din acestea rezulta ca a doua e mai mare decat prima.
b)
[tex]27^{13}-16*27^{12}=27^{12}(27-26)=27^{12}=(3^{3})^{12}=3^{36}\\
9^{19}-8*9^{18}=9^{18}(9-8)=9^{18}=(3^{2})^{18}=3^{36}\\[/tex]
Sunt egale
