👤
a fost răspuns

Calculati:
(2√8+3√5-7√2)(√72+√20-4√2)
7√48-3√27-2√12totul supra √75

Răspuns :

Capsunica35
(2√8+3√5-7√2)(√72+√20-4√2)=
(4√2+3√5-7√2)(6√2+2√5-4√2)=
(3√5-3√2)(2√5+2√2)=
30+6√10-6√10-24=6

(7√48-3√27-2√12)/√75=(28√3-9√3-4√3)/5√3=15√3/5√3=3