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Madalina417
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A+b+c=57si2a+b+2c=73calculati (a+c)×(5×a+2×b+5×c)

Răspuns :

Milumil2000
(a+c)=2x(a+b+c)-(2a+b+2c)=2x57-73=41

(5×a+2×b+5×c)=3x(2a+b+2c)-(a+b+c)=3x73-57=162

(a+c)×(5×a+2×b+5×c)=41x162=6642