Răspuns :
FeSO4
Masa=56+32+4•16=152
raport atomic: Fe:S:O
1:1:4
Trebuie raport procentual sau compozitie procentuala???
Masa=56+32+4•16=152
raport atomic: Fe:S:O
1:1:4
Trebuie raport procentual sau compozitie procentuala???
FeSO4
Raport procentual
%Fe = m Fe/m sulfat * 100 = 56/152 * 100 = 36.842%
%S = m S/m sulfat * 100 = 32/152 * 100 = 21.052%
%O = m O/m sulfat * 100 = 4*16/152 * 100 = 42.102%
36.842: 21.052: 42.102 = 12.208: 7.107: 14.034
Raport atomic
Fe: S: O = 1: 1: 4
Raport masic:
Fe: S: O = 56: 32: 64 = 7: 4: 8
Raport procentual
%Fe = m Fe/m sulfat * 100 = 56/152 * 100 = 36.842%
%S = m S/m sulfat * 100 = 32/152 * 100 = 21.052%
%O = m O/m sulfat * 100 = 4*16/152 * 100 = 42.102%
36.842: 21.052: 42.102 = 12.208: 7.107: 14.034
Raport atomic
Fe: S: O = 1: 1: 4
Raport masic:
Fe: S: O = 56: 32: 64 = 7: 4: 8