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Danydanyel985
a fost răspuns

[(3/2+2/3):la radical.din 169/36]^2012x[(-2)³]^5/(27)²=

ajutatima va rog imi trebuie pana la 12

Răspuns :

[(3/2+2/3):√169/36]^2012x[(-2)³]^5/(27)²=
= [ (9/6 + 4/6) : 13/6 ]^2012 × (-2)^15 / (27)² =
= ( 13/6 × 6/13)^2012 × (-2)^15/ (3³)² =
= 1^2012 × (-2)^15 / 3^6 = - 2^15 / 3^6

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