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Stiind ca 4ab+4ac+9a=106 si a=2, aflati b+c

Răspuns :

4ab+4ac+9a=106
4×2b+4×2c+9×2=106
8b+8c+18=106
8(b+c)=106-18
8(b+c)=88
b+c=88 : 8
b+c=11

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