Răspuns :
MCa(OH)₂= ACa+2(AO+AH)=40+2(16+1)=74g/mol
m=150g
n=m/M=150/74=2,027 moli Ca(OH)₂
Ca(OH)₂ se numeste hidroxid de calciu sau var stins
m=150g
n=m/M=150/74=2,027 moli Ca(OH)₂
Ca(OH)₂ se numeste hidroxid de calciu sau var stins
n = m/masa molara
masa molara = 40+2*(16+1) = 74 g/mol
n = 150/74 = 2.027 moli Ca(OH)2
masa molara = 40+2*(16+1) = 74 g/mol
n = 150/74 = 2.027 moli Ca(OH)2