Răspuns :
1)
V = n*22.4
n = 896/22.4 = 40 moli CO2
2)
n = m/masa molara
a) n = 14.2/(2*35,5) = 0.2 moli Cl2
b) n = 7.3/(1+35.5) = 0.2 kmoli HCl
V = n*22.4
n = 896/22.4 = 40 moli CO2
2)
n = m/masa molara
a) n = 14.2/(2*35,5) = 0.2 moli Cl2
b) n = 7.3/(1+35.5) = 0.2 kmoli HCl
1. n=V/Vm=896/22.4=40 moli CO2
2. a) MCl2=2ACl=2*35.5=71g/mol
n=m/M=14.2/71=0.2 moli Cl2
b) MHCl=AH+ACl=1+35.5=36.5kg/kmol
n=m/M=7.3/36.5=0.2 kmoli = 200moli HCl
2. a) MCl2=2ACl=2*35.5=71g/mol
n=m/M=14.2/71=0.2 moli Cl2
b) MHCl=AH+ACl=1+35.5=36.5kg/kmol
n=m/M=7.3/36.5=0.2 kmoli = 200moli HCl