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a fost răspuns

3+2 *[(2 la 27*3 la 35)] totu la a 2 :(2 la 56 * 3 la a 69)-4 la a 17: 2 la 33+35]

Răspuns :

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3+2×[(2²⁷×3³⁵)²:(2⁵⁶×3⁶⁹)-4¹⁷:2³³+35]=
3+2×[(2²⁷)²×(3³⁵)²:(2⁵⁶×3⁶⁹)-(2²)¹⁷:2³³+35]=
3+2×(2⁵⁴×3⁷⁰:2⁵⁶:3⁶⁹-2³⁴:2³³+35)=
3+2×(2⁵⁴:2⁵⁶×3⁷⁰:3⁶⁹-2¹+35)=
3+2×(2⁻²×3¹-2¹+35)=
3+2×2⁻²×3¹-2×2¹+2×35=
3+2⁻¹×3¹-2²+70=
73+0,5×3-4=
69+1,5=
70,5

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